How to perform j operations on array?

Given an array of integers, what's the most efficient way to perform j operations on the array where the value of j could be => or <= array.length?

I tried something like this…

function performJ(arr, j) {
  arr.sort((a, b) => b - a);
  let i = 0;
  while (j !== 0) {
   if (i < arr.length) {
     arr[i] = Math.ceil(arr[i] / 2)
   } else {
     // when i reaches arr.length, reset it to continue operations j
     i = 0;
     arr[i] = Math.ceil(arr[i] / 2)
   }
   // increment i, step through arr
   ++i;
   // decrement j as we perform operations on arr
   --j;
 }
 return arr.reduce((a, b) => a + b);
}

That works for a lot of cases, but for some reason it seems like large inputs of arr and j cause arithmetic operations in the while loop to get way off.

Thanks!

EDIT: Edited question for clarity. I previously had a solution that worked, but it took way too long. This solution's arithmetic is off, but works much faster.